Puzzle 2: Score century in 3 balls

Puzzle 2: If two batsmen in the match both r at 94 and last 3 balls remaining 7 to win both two batsmen got 100. How?
Show Solution

Solution:
a) Batsman A hit 6 run on first ball.
b) Batsman A again hit ball in air and start running, both batsmen cross over and A was caught by the fielder.
c) Then Batsman B takes the strike and hit the six again.

Advanced Problem: Now if players are not out.
Show Solution

Solution: Batsman A hit the ball and take 3-run, then the fielder throw the ball towards wicket but there was a overthrow and it goes out of boundary (for overthrow), so in total the player A should be awarded with 7 runs, but one run is short run by mistake so he was awarded by 6 runs only and Batsman B already on the strike as they took only 3 runs.
In Next ball Batsman B hit a six and makes his century and makes his 100 and wins the match.
Another Solution: 1st batsman hit ball it is stopped by hitting keeper helmet in the ground in this situation empire gives 5 runs .and next ball 1.then 2nd batsmen hit 6.